We are given the following inequality:
![-38\le-6-2x](https://img.qammunity.org/2023/formulas/mathematics/college/dgxfwa4c56in13c2m4ilqtfylvquwckdbc.png)
To solve for "x" we will add 2x to both sides:
![-38+2x\le-6](https://img.qammunity.org/2023/formulas/mathematics/college/71lr35srvqipufmwm4rj9bdl60b0j1ekwi.png)
Now we will add 38 to both sides:
![\begin{gathered} 2x\le-6+38 \\ 2x\le32 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/wax2fr9jiz9ajhhyg3wlsk6f6uukf68q56.png)
Now we divide both sides by 2:
![\begin{gathered} x\le(32)/(2) \\ \\ x\le16 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/mqid0dv6dyds5g8260br4v4iyx4gjr6v5v.png)
Therefore, the solution is the values of "x" that are smaller or equal to 16. This can be represented in the real line as follows:
We need to use all the points that are smaller (to the left) than 16. To represent the fact that 16 is also included in the solution we use a point on top of it.
In the case that 16 was not included then we would use a hollowed point on top of it.