Question

Solve the rational equation below:(5÷x) + (10x÷24)= 20÷3xA: X= -3,0B: X=+ or - 5C: X=+ or - 2D: X= -7, 2

Answer 1

`\begin{gathered} (5)/(x)+(10x)/(24)=(20)/(3x) \\ \text{Multiply both sides by x:} \\ 5+(10x^2)/(24)=(20)/(3) \\ \text{Multiply both sides by 3:} \\ 15+(30x^2)/(24)=20 \\ \text{Multiply both sides by 24:} \\ 360+30x^2=480 \\ \text{Subtract 360 from both sides:} \\ 30x^2=120 \\ \text{divide both sides by 30} \\ x^2=(120)/(30) \\ x^2=4 \\ \text{take the square root to both sides:} \\ x=\sqrt[]{4} \\ x=\pm2 \end{gathered}`

`c._{\text{ }}x=+2_{\text{ }}or_{\text{ }}-2`