Question

Consider the equation. Now the graph can be completed by drawing the curve through a point on the other side of the vertex. Find the point on the graph of this parabola that has the x-coordinate X = -3

Answer 1

Equation given:

`y=-2(x+4)^2-2`

Procedure:

To find the point on the graph in which x = -3, we have to replace this value in the given equation as follows:

`y=-2((-3)+4)^2-2`

Solving for y:

`y=-2(-3+4)^2-2`
`y=-2(1)^2-2`
`y=-2-2`

Answer:

`y=-4`

Coordinate: ( -3, -4 )