Question

Part BCalculate the molar mass for Mn3O4, an oxide of manganese.Express your answer to five significant figures.

Answer 1

To solve this question, we need to know the molar mass of Mn and O. We can look for it at the periodic table:

Mn = 54.938044 g/mol

O = 15.999 g/mol

Now, we multiply each molar mass by the number of atoms of each element in the compound Mn3O4 and sum the result.

There are 3 atoms of Mn and 4 atoms of O.

So:

(3x54.938044) + (4x15.999) = 228.81 g/mol

Answer: 228.81 g/mol