1 Answer

Francadaval · Answer 1 · 2023-04-18T09:43:46+0000

Starting with the given equation:

$-2+\sqrt[]{3x-2}=6$

Add 2 to both sides of the equation:

$\begin{gathered} \Rightarrow-2+\sqrt[]{3x-2}+2=6+2 \\ \Rightarrow\sqrt[]{3x-2}=8 \end{gathered}$

Square both sides of the equation:

$\begin{gathered} \Rightarrow(\sqrt[]{3x-2})^2=8^2 \\ \Rightarrow3x-2=64 \end{gathered}$

Add 2 to both sides of the equation:

$\begin{gathered} \Rightarrow3x-2+2=64+2 \\ \Rightarrow3x=66 \end{gathered}$

Divide both sides by 3:

$\begin{gathered} \Rightarrow x=(66)/(3) \\ \Rightarrow x=22 \end{gathered}$

Therefore, the solution to the given equation is:

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