Question

Calculate the total charge on the capacitors connected in series if the supply voltage is 500V. Sketch a circuit diagram and label this to show how the charges are located three capacitors 30µF, 20µF & 12µF connected in series

Answer 1

We know that the three capacitors are equivalent to:

`C_(eq)=6\mu F`

and we also know that the charge in a capacitor is given by:

`Q=CV`

hence the chargein the equivalent capacitor is:

`Q_(eq)=(6*10^(-6))(500)=3*10^(-3)=0.003\text{ }`

Hence, the charge in the equivalent capacitor is 0.003 C.

Now that we know that we have to remember that when capacitors are conected in series the charge in each of them is equal to the charge in the equivalent capacitor. Therefore, we conclude that the charge in each of the capacitor is 0.003 C.

The diagram is shown below: