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A normal distribution has a mean of 110 and a standard deviation of 8. Find the z-score for a data value of 80. Round to two decimal places

User Mnyikka
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We have a normal distribution that has a mean of 110 and a standard deviation of 8.

We have to find the z-score for a value of X = 80.

We can use the following expression to find the z-score:


z=(X-\mu)/(\sigma)

where μ = 110 and σ = 8.

Then, we can solve as:


z=(X-\mu)/(\sigma)=(80-110)/(8)=(-30)/(8)\approx-3.75

Answer: z = -3.75

User Jameila
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