We have the following:
we separate the figure into 2 two, the total area will be the sum of these, like this:
the area of each one is the base times the height in each case, therefore we calculate in each case the area
The small
![\begin{gathered} a=2\cdot2=4 \\ \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/18rvfo0xn8e92zxhk967ffjl957ut3fdos.png)
The big
![A=4\cdot5=20](https://img.qammunity.org/2023/formulas/mathematics/college/spc7kadyyryoxpwgayojm7zmlzpxkrea7c.png)
The total area is:
![A_T=4+20=24](https://img.qammunity.org/2023/formulas/mathematics/college/pany4vhy6xik5rgikzu9y8by4fa2j02eyr.png)
The answer is 24 square feet