Question

The width of a rectangle is 4n -5.5 feet and the length is 5.5n + 7 feet. Find the perimeter of the rectangle.

Answer 1

Given:

The width of a rectangle, w= 4n -5.5 feet.

The length of a rectangle, l= 5.5n+7 feet.

The perimeter of the rectangle is,

`\begin{gathered} P=2(l+w) \\ P=2(5.5n+7+4n-5.5) \\ P=2(9.5n+1.5) \\ P=19n+3 \end{gathered}`

Therefore, the perimeter of the rectangle is 19n+3.