120k views
2 votes
which compound inequality is equivalent to |ax-b| > c for all real numbers a, b, and c, where
c \geqslant 0

which compound inequality is equivalent to |ax-b| > c for all real numbers a, b-example-1
User Venge
by
4.6k points

1 Answer

3 votes

The compound inequality that represents the inequality is:


ax-b<-c

&


ax-b>c

***

We have that absolute value is the "magnitude" of a value [That is, is positive].

Now, when we have the following:


|a|Is the same as:[tex]aAnd also:[tex]-a-b

***

In other words, absolute value will always give as a solution a positive one, for example:


|-3|=3

Another example:


|3|=3

User Stefan Wick  MSFT
by
5.2k points