The polynomial:
![h=-16t^2+6](https://img.qammunity.org/2023/formulas/mathematics/college/ph1o81ndgkcf4ufv1n04u5bvhbzm3qs7ao.png)
represents how far the ball has fallen after t seconds (I will assume that h is measured in ft)
4) After 1 second means that t = 1. Substituting this value into the formula:
![\begin{gathered} h=-16\cdot1^2+6 \\ h=-16\cdot1^{}+6 \\ h=-16+6 \\ h=-10 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/1bid05ddjm6iz9fcv7535rei2a12ruw4le.png)
The ball fell 10 ft
5) Substituting with t = 3.2 seconds into the formula, we get:
![\begin{gathered} h=-16\cdot3.2^2+6 \\ h=-16\cdot10.24+6 \\ h=-163.84+6 \\ h=-157.84 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3karmz2hggfqypwvgsmpnc9b61csf3sno5.png)
The well has a depth of 157.84 ft