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Write in slope-intercept form5x + 10y = -10

1 Answer

3 votes

y=-(1)/(2)x-1

Step-by-step explanation

the equation of a line in slope-intercept point is given by:


\begin{gathered} y=mx+b \\ \text{where} \\ m\text{ is the slope} \\ b\text{ is the y-intercept} \end{gathered}

Step 1

isolate y


\begin{gathered} 5x+10y=-10 \\ \text{subtract 5x in both sides} \\ 5x+10y-5x=-10-5x \\ 10y=-10-5x \\ \text{divide both sides by 10} \\ (10y)/(10)=-(10)/(10)-(5)/(10)x \\ y=-1-(1)/(2)x \\ y=-(1)/(2)x-1 \end{gathered}

then


\begin{gathered} y=-(1)/(2)x-1\rightarrow y=mx+b \\ \text{slope}=-(1)/(2) \\ y-\text{intercept}=-1 \end{gathered}

I hope this helps you

User Wax
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