Question

Factor f(x) = 2x3 - 5x2 - 28x+ 15 into linear factors given that - 3 is a zero of f(x).f(x) = 2x3 - 5x2 - 28x + 15 =(Factor completely.)

Answer 1

We will solve as follows:

`2x^3-5x^2-28x+15=2(x-2x^3-x^2-28x+15)\mleft(x-2x^3-x^2-28x+15\mright)\mleft(x-2x^3-x^2-28x+15\mright)`