163k views
2 votes
Write an equation of the line in slope-intercept form (2,1) (0,-2)

User Abhshkdz
by
8.3k points

1 Answer

3 votes

Given the following coordinates of the two points that pass through the line.

Point 1 : 0, - 2

Point 2 : 2, 1

Let's determine the equation of the line:

Step 1: Let's determine the slope (m).


\text{ Slope = m = }(y_2-y_1)/(x_2-x_1)\text{ = }\frac{1\text{ - (-2)}}{2\text{ - 0}}
\text{ m = }\frac{1\text{ + 2}}{2}\text{ = }(3)/(2)

Step 2: Let's determine the y - intercept (b). Using the slope-intercept form: y = mx + b, plug in m = 3/2 and x,y = 0, -2.


\text{ y = mx + b}
\text{ -2 = (}(3)/(2))(0)\text{ + b}
\text{ b = -2}

Step 3: Let's complete the equation. Plug in m = 3/2 and b = -2 in y = mx + b.


\text{ y = mx + b}
\text{ y = (}(3)/(2))x\text{ + (-2)}
\text{ y = }(3)/(2)x\text{ - 2}

Therefore, the equation of the line is:


\text{ y = }(3)/(2)x\text{ - 2}

User Ihor Vyspiansky
by
8.0k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories