Question

25 in.17 in.A frame shop charges according to both the amount of framingneeded to surround the picture and the amount of glass needed tocover the picture17 ina. Find the area and perimeter of the trapezoid-shaped framed pictureto the rightb. Identify whether the frame has to do with perimeter or area and thesame with the glass.8 in.-55 ina. The area of the picture isand the perimeter isb. Choose the correct answer below.A. Both the frame and the glass have to do with area.O B. Both the frame and the glass have to do with perimeter.C. The frame has to do with area and the glass has to do with perimeter.OD. The frame has to do with perimeter and the glass has to do with area.

Answer 1

Perimeter of the trapezoid

To find the perimeter, you add the lengths and widths of all the sides of the shop.

Hence, the perimeter is

P = (17 + 25 + 17 + 55) in = 114 in.

Therefore, the perimeter is 114 in.

Area

To find the area, you use the formula

`A=(1)/(2)(a+b)h`

where,

`\begin{gathered} a=25in \\ b=55in \\ h=8in \end{gathered}`

Therefore,

`A=(1)/(2)(25+55)*8=80*4=320in^2`

Hence, the area of the trapezoid framed shop is 320in².

b) The frame has to do with perimeter and the glass would be the area because the area covers everything inside the frame.

Hence, the answer is Option D.