We are given the following equation

Let us solve the above equation.
Add 80 to both sides of the equation

Take square root on both sides of the equation
![\begin{gathered} √((x-1)^2)=√(80) \\ x-1=\pm\sqrt[]{80} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/bqeddr16svab1108rlxweqiz5x6xxdo8sv.png)
Add 1 to both sides of the equation
![\begin{gathered} x-1+1=\pm\sqrt[]{80}+1 \\ x=1\pm\sqrt[]{80} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/ji56nardvzv8j7oxszuh69u6fxqchn189l.png)
So, there will be two solutions
![x=1+\sqrt[]{80}\; \; and\; \; x=1-\sqrt[]{80}](https://img.qammunity.org/2023/formulas/mathematics/college/u575iwrfki7p4nhnxia80bu46m2m0r68le.png)
Simplify the root
![x=1+4\sqrt[]{5}\; \; and\; \; x=1-4\sqrt[]{5}](https://img.qammunity.org/2023/formulas/mathematics/college/c9gam782cmguntpvfap2t83j3gm4a6vtvb.png)
Therefore, the solution of the given equation is
![x=1+4\sqrt[]{5},\; 1-4\sqrt[]{5}](https://img.qammunity.org/2023/formulas/mathematics/college/dd1nyos05y5qus4xxugpizr466xlygl4gx.png)