Question

.Height has been rounded for computational ease.If X = 3 units, Y = 3 units, and Z = 6 units, then what is the surface area of the right triangular pyramid shown above

Answer 1

The surface area of the pyramid will be calculated below as

`\begin{gathered} A_s=(1)/(2)xy+(3)/(2)xz \\ x=3,y=3,z=6 \end{gathered}`

By substituting the values, we will have

`\begin{gathered} A_(s)=(1)/(2)xy+(3)/(2)xz \\ A_s=(1)/(2)*3*3+(3)/(2)*3*6 \\ A_s=(9)/(2)+27 \\ A_s=(9+54)/(2) \\ A_s=(63)/(2) \\ A_s=31.5unit^2 \end{gathered}`

Hence,

The final answer is

`\Rightarrow31.5units^2`