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Log(x) + log (4) = log(12)

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Solution:

The equation is given below as


logx+log4=log12

By applying the logarithm law of multiplication, we will have


logM+logN=logMN

By substituting the values, we will have


\begin{gathered} logx+log4=log12 \\ log(4* x)=log12 \\ 4x=12 \\ (4x)/(4)=(12)/(4) \\ x=3 \end{gathered}

Hence,

The value of x is


\Rightarrow x=3

User Yousif Abdalla
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