12.1k views
4 votes
In a small town named Danville, the population today is 6999. For the last sixyears, the population has grown by 20% every year. If the growth stay thesame, what is the expected population in Danville 4 years from today?

User Mrtentje
by
8.3k points

1 Answer

6 votes

We have that the population of Danville today is 6999.

The growth is 20% by year.

And they ask for the population in 4 years from today.

We just need to predict the population for the following 4 years, in other words, add 20% of the population each year.

1. 20% of 6999:


6999\ast(20)/(100)=1399.8

Then the population one year later will be:


6999+1399.8=8398.8\approx8398

For the second year:


8398+(8398\ast(20)/(100))=10077.6\approx10077

For the third year:


10077+(10077\ast(20)/(100))=12092.4\approx12092

For the fourth year:


12092+(12092\operatorname{\ast}(20)/(100))=14510.4\approx14510

Then, the correct answer is that the population in Danville 4 years from today will be 14510.

User Aperpen
by
7.5k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories