Question

In a small town named Danville, the population today is 6999. For the last sixyears, the population has grown by 20% every year. If the growth stay thesame, what is the expected population in Danville 4 years from today?

Answer 1

We have that the population of Danville today is 6999.

The growth is 20% by year.

And they ask for the population in 4 years from today.

We just need to predict the population for the following 4 years, in other words, add 20% of the population each year.

1. 20% of 6999:

`6999\ast(20)/(100)=1399.8`

Then the population one year later will be:

`6999+1399.8=8398.8\approx8398`

For the second year:

`8398+(8398\ast(20)/(100))=10077.6\approx10077`

For the third year:

`10077+(10077\ast(20)/(100))=12092.4\approx12092`

For the fourth year:

Then, the correct answer is that the population in Danville 4 years from today will be 14510.