Question

5(k+1)(5k+4)(k-8) = 0 solve by factoring

Answer 1

To solve the equation 5(k+1)(5k+4)(k-8) = 0 by factoring, set each factor equal to zero and solve for k. The solutions are k = -1, -4/5, and 8.

Step-by-step explanation:

To solve the equation 5(k+1)(5k+4)(k-8) = 0 by factoring, we need to set each factor equal to zero and solve for k.

1. 
   
3. Set k+1 = 0 and solve for k: k = -1
4. 
   
6. Set 5k+4 = 0 and solve for k: k = -4/5
7. 
   
9. Set k-8 = 0 and solve for k: k = 8

So the solutions to the equation are k = -1, -4/5, and 8.

Answer 2

5(k+1)(5k+4)(k-8) = 0

there are 3 possible solutions to this equation.

k + 1 = 0

k = -1

or

5k + 4 = 0

5k = -4

k = -4/5

or

k - 8 = 0

k = 8