Question

Two long, parallel wires separated by 0.199 m carry equal currents of 10.994 A in the same direction. Find the magnitude of the net magnetic field 0.244 m away from each wire on the side opposite the other wire . Express your answer in microTesla.

Answer 1

We will have the following:

`\begin{gathered} B_1=B_2=((4\pi\ast10^(-7)Tm/A)(10.944A))/(2\pi(0.244m)) \\ \\ \Rightarrow B_1=9.01147541...\ast10^(-6)T\Rightarrow B_1\approx9\mu T \end{gathered}`

Then:

`\begin{gathered} B_(net)=√((9\mu T)^2+(9\mu T)^2-2(9\mu T)(9\mu T)cos(48.132))\Rightarrow B_(net)=7.340196633...\mu T \\ \\ \Rightarrow B_(net)\approx7.34\mu T \end{gathered}`

So, the net magnetic field is approximately 7.34 micro tesla.