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A manufacturing machine has a 10% defect rate.If 4 items are chosen at random, what is the probability that at least one will have a defect? Round your answer to three decimal places.

User Jonnyhitek
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1 Answer

6 votes

Solution

Step 1


\begin{gathered} probability\text{ of defective p = 10\% = }(10)/(100)\text{ = 0.1} \\ \\ probability\text{ of not defective q = 1 - p = 1 - 0.1 = 0.9} \\ \end{gathered}

Step2

The probability that at least one will have a defect

= 1 - the probability that noon will have a defect

Step 3

Use the binomial distribution


\begin{gathered} =1\text{ - }^nC_rp^rq^(n-r) \\ n\text{ = 4, r = 0} \\ \\ =1-^4C_0(0.1)^0(0.9)^(4-0) \\ \\ =\text{ 1 - 1}*1*0.9*0.9*0.9*0.9 \\ \\ =\text{ 0.344} \end{gathered}

User Haja
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