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You hang a mass of 1.541 kg on a spring and let it slowly stretch the spring. It itstretches the spring a total of 0.428 m, how much energy is stored in the spring? Take gto be 9.81 m/s2

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ANSWER

3.24 J

Step-by-step explanation

Let's draw a diagram of this situation first:

As we can see, after the spring stretches, we have two forces acting upon the mass: the spring force and the gravity force (also known as the weight of the mass). Since the mass is not moving at this moment, by Newton's Second Law of Motion:


\begin{gathered} F_s-F_g=0 \\ \text{ therefore} \\ F_s=F_g \end{gathered}

So the spring force is:


F_s=mg

Now, the potential energy of the spring - which is the energy stored in the spring, is:


U_s=(1)/(2)\cdot\Delta y\cdot(-k\cdot\Delta y)=(1)/(2)\cdot\Delta y\cdot F_s

So for this problem, the potential energy is:


U_s=(1)/(2)\cdot\Delta y\cdot m\cdot g

Replacing with the values:


U_s=(1)/(2)\cdot0.428m\cdot1.541\operatorname{kg}\cdot9.81m/s^2=3.24J

We have that the energy stored in the spring is 3.24 J, rounded to the nearest hundredth.

You hang a mass of 1.541 kg on a spring and let it slowly stretch the spring. It itstretches-example-1
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