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The answer is D, but I need help showing work.

The answer is D, but I need help showing work.-example-1

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\begin{gathered} a_(n=16+5n) \\ at\text{ n=1} \\ a_1=16+5 \\ a_1=21 \\ a_2=16+5*2 \\ a_2=26 \\ a_3=16+5*3 \\ a_3=31 \\ a_4=16+5*4 \\ a_4=36 \end{gathered}

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