Question

A car starts from rest and accelerates at 9.54m/s2 for 6.5sec. What is the distance covered by the car?

Answer 1

Explanation:

If a body starts from rest, with an acceleration of a for time t, then the distance D covered by is given by

`D=(1)/(2)at^2`

Now, in our case we have a = 9.54 m/s^2 and t = 6.5 s; therefore,

`D=(1)/(2)\cdot(9.54m/s^2)\cdot(6.5s)^2`

which upon simplification gives

`\boxed{D=201.5325m}`

Hence, the distance covered by the car is about 202 meters.