Potassium permanganate (KMnO4) is used as an explosive agent. How many moles are there if we have 105.66 grams of potassium permanganate?

Question

asked Mar 1, 2023 64.4k views

1 Answer

Dmitry Andreev · Answer 1 · 2023-03-07T02:41:06+0000

0.669mole

The formula for calculating the number of moles is expressed as:

$moles=\frac{Mass}{Molar\text{ mass}}$

Given the following parameters

$\begin{gathered} Mass\text{ of }KMnO_4=105.66grams \\ molar\text{ mass of }KMnO_4=158.034g\text{/mol} \end{gathered}$

Substitute the given parameters into the formula

$\begin{gathered} mole\text{ of KMnO}_4=\frac{105.66g}{158.034g\text{/mol}} \\ mole\text{ of KMnO}_4=0.669mole \end{gathered}$

Hence the molar mass of KMnO4 that were there is 0.669mole