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Potassium permanganate (KMnO4) is used as an explosive agent. How many moles are there if we have 105.66 grams of potassium permanganate?

1 Answer

4 votes

Answer:

0.669mole

Explanations:

The formula for calculating the number of moles is expressed as:


moles=\frac{Mass}{Molar\text{ mass}}

Given the following parameters


\begin{gathered} Mass\text{ of }KMnO_4=105.66grams \\ molar\text{ mass of }KMnO_4=158.034g\text{/mol} \end{gathered}

Substitute the given parameters into the formula


\begin{gathered} mole\text{ of KMnO}_4=\frac{105.66g}{158.034g\text{/mol}} \\ mole\text{ of KMnO}_4=0.669mole \end{gathered}

Hence the molar mass of KMnO4 that were there is 0.669mole

User Dmitry Andreev
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