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What is the mass of 5.6 x 10^26 molecules of Al2O3?

User Ruzard
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1 Answer

2 votes

Answer:

94846.5grams

Explanations

Given the following parameters

molecules of Al2O3 = 5.6 x 10^26 molecules

According to the avogadros constant

1 mole = 6.02 * 10^23 molecules

Convert molecules to moles


\begin{gathered} moles\text{ of Al}_2O_3=(5.6*10^(26))/(6.02*10^(23)) \\ moles\text{ of Al}_2O_3=0.9302*10^3 \\ moles\text{ of Al}_2O_3=930.2moles \end{gathered}

Convert the moles to mass


\begin{gathered} mass\text{ of Al}_2O_3=moles* molar\text{ mass} \\ mass\text{ of Al}_2O_3=930.2\cancel{moles}*\frac{101.96g}{\cancel{mole}} \\ mass\text{ of Al}_2O_3=94,846.5grams \end{gathered}

Therefore the mass of 5.6 x 10^26 molecules of Al2O3 is 94846.5grams

User Ulan Murzatayev
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