A) Notice that the two mixed fractions are equivalent to
![\begin{gathered} 4(1)/(3)=4+(1)/(3) \\ \text{and} \\ 3(2)/(3)=3+(2)/(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/al05bvrd8fa2yxal0jr2i0u0nwepitecw4.png)
Jill transformed 4 into 12/3 and 3 into 9/3, and then she subtracted the second quantity from the first one. She forgot about the 1/3 and 2/3.
B) The correct calculation is
![\begin{gathered} 4(1)/(3)-3(2)/(3)=(4+(1)/(3))-(3+(2)/(3))=4+(1)/(3)-3-(2)/(3)=(4-3)+((1)/(3)-(2)/(3))=1+(-(1)/(3))=(2)/(3) \\ \Rightarrow4(1)/(3)-3(2)/(3)=(2)/(3) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/dtktim2ivhr917yl13clpbmmcz969ios45.png)
The answer to part B) is 2/3