Question

In ΔDEF, the measure of ∠F=90°, the measure of ∠D=67°, and FD = 7.4 feet. Find the length of EF to the nearest tenth of a foot.

Answer 1

14.2 ft

Explanation:

tan 66° = 32/ FD

FD = 32 / tan 66° = 32 / 2.246 = 14.2

hope it helped you

Answer 2

17.4

Explanation:

\tan D = \frac{\text{opposite}}{\text{adjacent}}=\frac{x}{7.4}

tanD=

adjacent

opposite

​

=

7.4

x

​

\tan 67=\frac{x}{7.4}

tan67=

7.4

x

​

7.4\tan 67=x

7.4tan67=x

Type into calculator and round to the nearest tenth of a foot.