This problem is about conditional probability, where:
P(A | B) = Probability of A given B
P(A ∩ B) = Probability of A and B
P(B) = Probability of B
And the relation with the terms above is:
![P(A\text B) = (P(A\cap B))/(P(B))](https://img.qammunity.org/2023/formulas/mathematics/college/x7jupiyohfz168mef3i1xptp06g23ws002.png)
In order to calculate de probabilities we need to sum over the students:
Total number of students = 100 (we just sum all the numbers in the table)
Now, the events are:
A = take the bus
B = be a senior student
P(A ∩ B) = # of senior students that take the bus / total number of students = 5 / 100 = 0.05
P(B) = # of senior students / total number of students = 35 / 100 = 0.35
So, using the formula of above:
![P(A\text \frac{P(A\text{ }\cap\text{ B)}}{P(B)}\text{ = }(0.05)/(0.35)\text{ = }(1)/(7)=0.142857](https://img.qammunity.org/2023/formulas/mathematics/college/90opvily3odt2x2us4957y7iyod4rtf4yj.png)
Or:
![P(A|B)\text{ = 14.29 \%}](https://img.qammunity.org/2023/formulas/mathematics/college/4tb80rw1k29pav2m3p61pcs5ot32gd69yg.png)