Given,
The number of sides in the cube is 6.
The numbered value in the cube is 1, 2, 3,4, 5, 6.
Required:
The probability of rolling an odd number and then rolling an odd number.
The probability of getting odd number number on first roll is,
![\begin{gathered} P(odd)=(3)/(6) \\ =(1)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4t2tw660x4do7ava3wyk8fjvwodfkabs7d.png)
The probability of getting odd number number on second roll is,
![\begin{gathered} P(odd)=(3)/(6) \\ =(1)/(2) \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/4t2tw660x4do7ava3wyk8fjvwodfkabs7d.png)
The probability of getting odd than odd,
![\begin{gathered} P=(1)/(2)*(1)/(2) \\ =0.5*0.5 \\ =0.25 \\ =25\text{ \%} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/msrnjwx7pvjvolxm198so372c3ioazbauu.png)
Hence, the probability of rolling an odd number and then rolling an odd number is 25%.