Question

Find the variance x 5,6,7,8,9P(X=x) 0.1, 0.1, 0.3, 0.1, 0.4

Answer 1

The variance is given by:

`\sigma^2=(\Sigma(x-\mu)^2)/(N)`

Therefore:

`\begin{gathered} \mu=(5\cdot0.1+6\cdot0.1+7\cdot0.3+8\cdot0.1+9\cdot0.4)/(5) \\ \mu=1.52 \end{gathered}`
`\begin{gathered} \sigma^2=(160.152)/(5) \\ \sigma^2\approx32.0 \end{gathered}`