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Factor x3 – 3x2 – 4x + 12 completely using long division if (x – 2) is a factor. (x – 2)(x – 2)(x + 3) option 1(x – 2)(x + 2)(x + 3) option 2(x – 2)(x + 2)(x – 3) option 3 (x – 2)(x – 2)(x – 3) option 4

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4 votes

Answer:

Explanation:

72

User Andrew Bucknell
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Given the cubic function


x^3-3x^2-4x+12

To get the other factors using the long division method

Having obtained the result of


\begin{gathered} div\text{iding } \\ x^3-3x^2-4x+12 \\ by \\ x-2 \end{gathered}

which gives x²-x-6

The next step will be to factor x²-x-6


x^2-x-6=(x+2)(x-3)

Combining the factors, we will obtain


(x-2)(x+2)(x-3)

The answer is option 3

Factor x3 – 3x2 – 4x + 12 completely using long division if (x – 2) is a factor. (x-example-1
User Nivin V Joseph
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