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What’s the equation if the center of the circle is (-7, 1) with a radius of 15

User Kyle Dodge
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1 Answer

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By definition, the general equation for a circle is the one shown below:


\left(x-h\right)^2+(y-k)^2=r^2

Where (h,k) is the center of the circle and "r" is the radius.

In this case, you know that the center of the circle is (-7, 1) and its radius is 15. Then, you can identify that:


\begin{gathered} h=-7 \\ k=1 \\ r=15 \end{gathered}

Finally, substituting these values into the general equation for the circle shown above and simplifying, you get that the equation of this circle is the following:


\begin{gathered} \left(x-(-7)\right)^2+(y-1)^2=15^2 \\ (x+7)^2+(y-1)^2=225 \end{gathered}

User Ali Torki
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