for each value of x, substitute with x at (5x + 1)
if x = 0 so, 5x + 1 = 5 * 0 + 1 = 1
if x = 1 so, 5x + 1 = 5 * 1 + 1 = 6
if x = 2 so, 5 x + 1 = 5 * 2 + 1 = 11
if x = 3 so, 5x + 1 = 5 * 3 + 1 = 16
if x = 4 so, 5x + 1 = 5 * 4 + 1 = 20 + 1 = 21
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