Question

Calculate the amount of heat, in joules, needed to raise 50.0 g of ice from 50.0°C to 75.0°C. Note, the specific heat capacity of ice is 2.09 J / g 0 C.

Answer 1

In this question, we have a situation in which we have to use the Calorimetry formula, which is how much heat was released or absorbed (in Joules), after we had a change in temperature of a compound. The formula for this Calorimetry question is:

Q = mcΔT

Where:

Q = is energy as Heat

m = mass in grams, 50 grams

c = is the specific heat capacity, 2.09 J/g°C

ΔT = the change in temperature, calculated as Final Temperature - Initial T

75 - 50 = 25

Now we add these values into the formula:

Q = 50 * 2.09 * 25

Q = 2612.5 Joules are needed