Question

A student decreases the temperature of a 419 cm3 balloon from 570 K to 210 K.Assuming constant pressure, what should the new volume of the balloon be?Round your answer to one decimal place.

Answer 1

Given:

The initial volume of the balloon, V₁=419 cm³=419×10⁻⁶ m³

The initial temperature of the balloon, T₁=570 K

The final temperature of the balloon, T₂=210 K

To find:

The final volume of the balloon.

Step-by-step explanation:

From Charle's law,

`\begin{gathered} (V_1)/(T_1)=(V_2)/(T_2) \\ \Rightarrow V_2=(V_1)/(T_1)* T_2 \end{gathered}`

On substituting the known values,

`\begin{gathered} V_2=(419*10^(-6))/(570)*210 \\ =154.4*10^(-6)\text{ m}^3 \\ =154.4\text{ cm}^3\text{ } \end{gathered}`

Final answer:

The volume of the balloon will be 154.4 cm³