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Find the equation of the line in standard form that passes through the following points. Eliminate any fractions and simplify your answer

Find the equation of the line in standard form that passes through the following points-example-1

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Answer:

7x-10y=57

Explanation:

The following two points are on a line:


\begin{gathered} (x_1,y_1)=(-9,-12) \\ (x_2,y_2)=(1,-5) \end{gathered}

To find the equation of the line, use the two-point formula for the equation of a line.


$$(y-y_1)/(x-x_1)=(y_2-y_1)/(x_2-x_1)$$

Substitute the given points:


(y-(-12))/(x-(-9))=(-5-(-12))/(1-(-9))

Then simplify:


\begin{gathered} (y+12)/(x+9)=(-5+12)/(1+9) \\ (y+12)/(x+9)=(7)/(10) \end{gathered}

Cross multiply:


10(y+12)=7(x+9)

Open the bracket:


\begin{gathered} 10y+120=7x+63 \\ 7x-10y=120-63 \\ 7x-10y=57 \end{gathered}

The equation of the line is 7x-10y=57.

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