Question

The circle below is centered at (10, 4) and has a radius of 4. What is itsequation?yX-10A. (x-4)² + (y-10)² = 4B. (x-10)2 + (y-4)² = 4C. (x-4)2 + (y-10)² = 16D. (x-10)² + (y- 4)² = 1610-10-10

Answer 1

Given:

There is a circle given with center (10,4) and radius 4

Required:

We need to find the equation of circle

Step-by-step explanation:

The equation of circle is

`(x-h)^2+(y-k)^2=r^2`

where (h,k) is the coordinate of center and r be the radius

so (h,k)=(10,4)

and r=4

now substitute the values in the equation of circle

`\begin{gathered} (x-10)^2+(y-4)^2=4^2 \\ (x-10)^2+(y-4)^2=16 \end{gathered}`

Final answer:

The equation of given circle is

`(x-10)^(2)+(y-4)^(2)=16`