Question

What is the equation of the line that is parallel to -3y = 4x + 10 and passes through the point (-18, 7)?

Answer 1

`\begin{gathered} \text{The equation is,} \\ -3y=4x+10 \\ y=-(4)/(3)x-(10)/(3) \\ So,\text{ the slope is}\Rightarrow m=-(4)/(3) \\ \text{Now for parallel line equation} \\ y-y_1=m(x-x_1) \\ y-7=-(4)/(3)(x+18) \\ 3y-21=-4x-72 \\ 3y=-4x-51 \\ y=-(4)/(3)x-17 \end{gathered}`