Question

1.

Calculate the resistance between points A and B (RAB) for the following resistor networks:
Figure 1
All resistors 5000
Figure 2
All resistors 1 k2
Figure 3
A
2k03 352
B В
4700
1000 $
B
A
ww
Figure 6
Figure 4
250 Ω
Figure 5
All resistors 2.2 k12
.B
23003
4700
31000
47002
33003
AW
94002
B

Answer 1

The answer is below

Step-by-step explanation:

1)

`R_(AB)=(500+500)||(500+500)\\\\R_(AB)=1000||1000\\\\R_(AB)=(1000*1000)/(1000+1000) \\\\R_(AB)=500\ \Omega`

2)

`R_(AB)=1000\|(1000+1000+1000)\\\\R_(AB)=1000||3000\\\\R_(AB)=(1000*3000)/(1000+3000) \\\\R_(AB)=750\ \Omega`

3)

Because of the short, the resistance is zero.

`R_(AB)=0`

4)

`R_(AB)=940\ \Omega`

5)

`R_(AB)=2200||2200||(2200+2200)\\\\R_(AB)=2200||2200||4400\\\\(1)/(R_(AB))=(1)/(2200) +(1)/(2200) +(1)/(4400) \\\\(1)/(R_(AB))=(5)/(4400)\\\\R_(AB)=880`

6)

`R_(AB)=(220+100)||470||330\\\\R_(AB)=320||470||330\\\\(1)/(R_(AB))=(1)/(320) +(1)/(470) +(1)/(330) \\\\R_(AB)=120.7\ \Omega`