Question

C=5 and d=4
`6 {c}^(2) - 5d + 8`what is the value?

Answer 1

Given c = 5 and d = 4

`\begin{gathered} \text{ 6c}^2-5d+\text{ 8 } \\ \text{Substituting the values of c and d into 6c}^2-5d+\text{ 8 , we have} \\ \text{6c}^2-5d+\text{ 8 }=6(5)^2-5(4)+\text{ 8} \\ =6(25)\text{ - 20 + 8} \\ =150-12 \\ =138 \\ \\ \text{The value of the expression is 138} \end{gathered}`