Question

Answer question number 16. The question is in the image.

Answer 1

The exercises refer to hydrocarbons. Depending on the type of bond, it will be the termination of the name of the molecule.

For a single bond: End with the suffix -ane

For double bond: Ends in -ene

For triple bond: Ends in -yne

Let's look at each particular case

a) Heptene

Hept- means 7 carbons, so we have a compound with 7 carbons and one double bond. The formula will be:

`CH_2=CH-CH_2-CH_2-CH_2-CH_2-CH_3`

c)Hexane

6 carbons with a simple bond

`CH_3-CH_2-CH_2-CH_2-CH_2-CH_3`

d)Pentane

5 carbons with a simple bond

`CH_3-CH_2-CH_2-CH_2-CH_3`

e)Propyne

3 carbons with a triple bond

`CH\equiv C-CH_3`