Question

A high school baseball player has a 0.303 batting average. In one game, he gets 6 at bats. What is the probability he will get at least 3 hits in the game? (Give your answer as a decimal rounded to 3 places.)

Answer 1

Given:

`\begin{gathered} Probability(success)=0.303 \\ Number-of-trials=6 \end{gathered}`

To Determine: The probability of at least 3 hits

Solution

This is a binomial distribution case

`P(X\ge3)=1-P(X\leq2)`

The formula for finding binomial expansion is

From the given

`\begin{gathered} n=6 \\ x=3 \\ p=0.303 \\ q=1-0.303=0.697 \end{gathered}`

Using calculator

`\begin{gathered} P(x\ge3)=0.261266 \\ \approx0.261 \end{gathered}`