140,219 views
0 votes
0 votes
R2/r12 A. r10B. 1/r6C.1/r10D. r8E. r6

User George Leow
by
3.3k points

1 Answer

2 votes
2 votes

this is


(r^2)/(r^(12))=r^(2-12)=r^(-10)=(1)/(r^(10))

answer: C

User Nodrog
by
3.3k points