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(Math Help Quick Lots of points please thanks) 3 (look for 2nd picture too for bottom half of page)

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2 Answers

2 votes

Given:


\overline{PX}\:is\: ⊥\:bisector\:of \:\overline{YZ}

To prove:


YP=ZP

Proof:


YX=XZ \\ \sf[Since \: PX \: is \: perpendicular \: bisector, \\ \sf\: both \: parts \: of \: the \: bisected \: line \: are \: equal]


ΔPXY ≅ ΔPXZ \\ \tt [by \: sss \: congruence \: rule]


YP = ZP \\ \bf \: [by \: CPCT]

User Quentin Morrier
by
8.0k points
10 votes

Answer:

Given
\overline{PX} is the
\perp bisector of
\overline{YZ}


\overline{YX} =
\overline{XZ}

⇒ ΔPXY ≅ ΔPXZ

⇒ YP = ZP

Explanation:

Given
\overline{PX} is the
\perp bisector of
\overline{YZ}


\overline{YX} =
\overline{XZ}

⇒ ΔPXY ≅ ΔPXZ

⇒ YP = ZP

User Stefjnl
by
8.4k points

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