Question

Help me, please this is the 4th time I've reached out to a tutor

Answer 1

Verify each option

A

`\sqrt[3]{64}\cdot\sqrt[4]{81}`

Remember that

64=4^3

and

81=3^4

substitute

`\sqrt[3]{64}\cdot\sqrt[4]{81}=4\cdot3=12`

option A simplification is correct

Option B

we have

`\sqrt[3]{x^3}\cdot\sqrt[3]{x^3y^6}=x\cdot xy^2=x^2y^2`

option B simplification is correct

Option C

`\sqrt[3]{x^2y^2}\cdot\sqrt[]{4y^2}=2y\cdot\sqrt[3]{x^2y^2}`

option C simplification is correct

Option D

we have

`\sqrt[4]{9x^4}\cdot\sqrt[4]{16x^4}=\sqrt[4]{144x^8}=2x^2\sqrt[4]{9}=2x^2\sqrt[]{3}`

option D, simplification is not correct

therefore

the answer is option D