Question

When resting, a person has a metabolic rate of about 4.70x10^5 joules per hour. The person is submerged neck deep into a tub containing no 812kg of water at 23.07 degrees Celsius. If the heat from the person goes only into the water, by how much will the water temperature temperature increase after 43 minutes of immersion?

Answer 1

Given

Rate of metabolic rate,

`Q=4.70*(10^5J)/(hr)`

Mass of water,

`m=812kg`

The initial temperature,

`T=23.07^oC`

Step-by-step explanation

The heat transferred in 43 minutes is given by

`\begin{gathered} Q*(43)/(60)=mc(T_f-T_i) \\ \Rightarrow4.70*10^5*(43)/(60)=812*4180(T_f-28) \\ \Rightarrow T_f=28.099^oC \end{gathered}`

Conclusion

The temperature increase to 28.099 degC