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Solve the system of linear equations by substitutionx=17-4yy=x-2

1 Answer

5 votes

Let:


\begin{gathered} x=17-4y_{\text{ }}(1) \\ y=x-2_{\text{ }}(2) \end{gathered}

Replace (1) into (2):


\begin{gathered} y=17-4y-2 \\ solve_{\text{ }}for_{\text{ }}y\colon \\ y+4y=15 \\ 5y=15 \\ y=(15)/(5) \\ y=3 \end{gathered}

Replace the value of y into (1):


\begin{gathered} x=17-4(3) \\ x=17-12 \\ x=5 \end{gathered}

User Pierrick HYMBERT
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