Question

So basically, I need help with finding angles AG and CI :) please be specific!!

Answer 1

Given that triangles PIC and GRA are similar, then the next proportion must be satisfied:

`(PI)/(GR)=(IC)/(RA)=(PC)/(GA)`

Replacing with data and solving for AG,

`\begin{gathered} (91)/(119)=(104)/(AG) \\ 91\cdot AG=104\cdot119 \\ AG=(12376)/(91) \\ AG=136 \end{gathered}`

Replacing with data and solving for CI,

`\begin{gathered} (91)/(119)=(CI)/(102) \\ (91\cdot102)/(119)=CI \\ (9282)/(119)=CI \\ 78=CI \end{gathered}`